Using leaner combination method what is the solution to the system of linear equations 7x-2y=-20 and 9x+4y=-6

x = -2 and y = 3

Step-by-step explanation:

In linear combination method we try one of the variables from bopth of equations by

first making the variable equal in vlaue

then either subtracting or adding the two equation as required to eliminate the variable.

7x-2y=-20   equation 1

and 9x+4y=-6   equation 2

we see that y has

has value -2 and +4

4 = 2*2

thus, if we multiply equation1 with 2 we will give value for variable y as 4y and hence y can be eliminated easily.

7x-2y=-20  

multiplying the LHS and RHS with 2

2(7x-2y)=-20 *2

=> 14x - 4y = -40   eqaution 3

now that we have got 4y

lets add equation 2 and equation 3

  9x +4y=   -6

+14x - 4y = -40

=> 23x + 0 =  -46

x = -46/23 = -2

Thus, x = -2

substituitinng x = -2 in 7x-2y=-20

7*-2 -2y=-20

=> -14 -2y = -20

=> -2y = -20+14 = -6

=> y = -6/-2 = 3

Thus, y = 3

solution is x = -2 and y = 3

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3

(- 1, 0 )

step-by-step explanation:

an x- intercept is where the function crosses the x- axis.

to find the x- intercept/s look for the value of x when f(x) = 0

from the given table there are 3 values of x where f(x) = 0

when x = - 1, x = 2, x = 3

the one that is listed is (- 1, 0 )