For this system,
y1 ′ = 2y1 − 4y2
y2 ′ = y1 − 3y2
y1 (0) = 3
y2 (0) = 0
...
Mathematics, 29.07.2020 17:01 tynan74
For this system,
y1 ′ = 2y1 − 4y2
y2 ′ = y1 − 3y2
y1 (0) = 3
y2 (0) = 0
h = 0.1
Solve in MATLAB or VBA and plot with 10 steps.
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