The table of values represents a linear function g(x), where x is the number of days that have passed and g(x) is the balance in the bank account: x g(x)
0 $1,500
2 $1,350
4 $1,200

Part A: Find and interpret the slope of the function. (3 points)
Part B: Write the equation of the line in point-slope, slope-intercept, and standard forms. (3 points)
Part C: Write the equation of the line using function notation. (2 points)
Part D: What is the balance in the bank account after 5 days? (2 points)

Part A:

The y-intercept is $1,500

The x-intercept is 20 days

Part B:

Equation of the line in point-slope form is  y - 1350 = -75×(x - 2)

Equation of the line in slope-intercept form is y = -75·x + 1500

Equation of the line in standard form  is y + 75·x = 1500

Part C:

f(x) = -75·x + 1500

Part D:

$1,125

Step-by-step explanation:

The information given are;

x,                 g(x)

0,                 $1,500

2,                 $1,350

4,                 $1,200

The equation of a straight line relation between the x, and y, coordinates in slope and intercept form is  y = m·x + c

Where;

m = The slope

c = The y-intercept

From the data, we have two points, (x₁, y₁), (x₂, y₂) given as (0, 1,500), (2, 1350);

The y-intercept = y at x = 0 = 1,500

y = -75·x + 1500

x = 1500/75 = 20

Part B:

The equation in point-slope form is y - y₁ = m×(x - x₁)

Which gives;

Equation of the line in point-slope form is  y - 1350 = -75×(x - 2)

Equation of the line in slope-intercept form is y = -75·x + 1500

Equation of the line in standard form  is y + 75·x = 1500

Part C:

The equation of the line using function notation is f(x) = -75·x + 1500

Part D:

The balance in the bank after 5 days is f(5) = -75 × 5  + 1500 = $1,125

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step-by-step explanation: