EXAMPLE 3 A wire takes the shape of a semicircle x2 + y2 = 9, y ≥ 0, and is thicker near its base than near the top. Find the center of mass of the wire if the linear density at any point is proportional to its distance from the line y = 4. SOLUTION As in this example we use the parametrization x = 3 cos(t), y = 3 sin(t), 0 ≤ t ≤ π, and find that ds = 3 dt. The linear density is rho(x, y) = k(4 − y)

last option

step-by-step explanation:

given that δdef is right and isoceles,

assuming that side df is the hypotenuse means that de an ef are the other 2 sides that intersect at 90° and are of equal length.

because they are of equal length, we can say that they are congruent

because they intersect at 90°, their slopes must be opposite reciprocals.

only the last option satisfies these conditions.

pretty sure 750 each month!

step-by-step explanation:

idk

step-by-step explanation: