A college requires all freshmen to take Math and English courses. Records show that 24% receive an A in English course, while only 18% receive an A in Math course. Altogether, 35.7% of the students get an A in Math course or English course. What is the probability that a student who receives an A in Math course will also receive an A in English course

7.3%

Step-by-step explanation:

Let M = Maths

E = English

P(M ∪ E) = P(M) + P(E) - P( M ∩ E)

From the question:

P(M ∪ E) = 35.7%

P(M) = 18%

P(E) = 24%

P( M ∩ E) = unknown

35.7% = 18% + 24% - P( M ∩ E)

35.7% = 42% - P( M ∩ E)

P( M ∩ E) = 42% - 35.7%

P( M ∩ E) = 7.3%

Therefore, the probability that a student who receives an A in Math course will also receive an A in English course is 7.3%.

answer: sorry i can't you.

step-by-step explanation:

if x = 1, then the answer is 3.5