In the diagram below, BD is parallel to XY. What is the value of y?

The value of y is 67°.

Step-by-step explanation:

Here, given that;

BD is parallel to XY. let EF be a transversal line meeting BD at O and XY at P.

now, angle XQF = 67°

now, angle XQF + angle YQF=180° (being linear pair)

or, 67°+angle YQF =180°

or, angle YQF=180°-67°

therefore angle YQF = 113°.

now, angle YQF + angle PQY=180° (being linear pair).

now, 113°+angle PQY = 180°.

or, angle PQY = 180°-113°.

therefore, angle PQY =67°.

again, angle EPD= angle PQY (being corresponding angles).

or, y°= 67°.

Therefore the value of y is 67°.

hope it helps...

after simplifying it i got: -36.25 as my answer. hope that !

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