4. A number m is such that when it is divided by 30, 36, and 45 the remainder is always 7, find the smallest possible value of m

187

Step-by-step explanation:

A number m is such that when it is divided by 30, 36 and 45 the remainder is always 7.

We should first find the LCM of 30, 36 and 45

We get that the LCM of the three numbers is 280 (working attached).

So now;

= 6

= 5

= 4

But we need a number that leaves a remainder of 7 so we add 7 to 180 to get; 180 + 7 = 187.

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

sine

step-by-step explanation: