A total of $5900 is invested, part at 11% simple interest and part at 7%. If the total annual return from the two investments is $ 537.00, how much is invested at each rate? How much was invested at 11% ? $_

Step-by-step explanation:

y = 5900 - x

Simple interest = Prt

Simple interest on $x = x * 0.11 * 1 = 0.11x

Simple interest on $ (5900 - x) = (5900 - x) * 0.07 * 1

                                                   = (5900 - x) * 0.07

                                                   = 5900 * 0.07 - x * 0.07

                                                   = 413 - 0.07x

Return from tow investment =  $ 537

0.11x + 413 - 0.07x = 537  

Add the like terms

0.04x + 413 = 537

Subtract 413 for both sides

0.04x = 537 - 413

0.04x = 124

x = 124 /0.04

x = 3100

y = 5900 -  3100 = 2800

x = $ 3100

y = $ 2800  

(0,,,0)

step-by-step explanation:

the table of x and y values is shown in the attached pic(part of question)

we have to decide according that graph

given points are (0, 0) (–1, 0), (2, 0)

when we graph these points on graph they show an increasing line as shown in the attached pic