The endpoints of WX are W(2,-7) and X(5,-4). What is the length of WX?

Step-by-step explanation:

Using the formula for calculating the distance between two points to calculate the length of WX.

D = √(y₂-y₁)²+(x₂-x₁)²

Given the endpoints W(2,-7) and X(5,-4), x₁ = 2, y₁ = -7, x₂ = 5 and y₂ = -4

Substituting this values into the formula to get the length of WX will give;

WX = √(-4-(-7))²+(5-2)²

WX = √(-4+7)²+3²

WX = √3²+3²

WX = √18

WX = √2*9

WX = 3√2 units

Hence the length of WX is 3√2 units.

an advantage of the standard deviation is that it increases as the dispersion of the data increases. e. the interquartile range is preferred when the data are not skewed or no have outliers. an advantage of the standard deviation is that it uses all the observations in its computation.

ummm seems that u didnt post the attachement !