Part I: Binomial Probability Histograms The frame below initially shows a binomial probability histogram with parameters n = 5 and p = 50%. Find one of the bins for which the normal approximation and the binomial probability differ most. Problem 1 One of the bins for which the binomial probability differs most from the normal approximation is the bin centered at (type an integer) (Q1) , where the absolute value of the difference in areas is (Q2) Change the probability p of success to 32%, and find the bin for which the difference between the normal approximation and the binomial probability is largest. Problem 2 For p= 32%, the absolute value of the largest difference between the area of one bin in the binomial probability histogram and the normal approximation is (Q3)

the answer is 0.3175 hope that you ^w^

also you might actually want to put this picture up if you want people to solve it luckily i remember this question

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step-by-step explanation:

34.5 cm

step-by-step explanation:

generally for a circular segment of angle, θ° and radius r

arc length

= (θ/360) x circumference

= (θ/360) x 2πr

in our case, θ = 60°, π=3.142 and r = 33 cm

substitute into above formula

arc length

= (60/360) x 2(3.142)( 33) = 34.5 cm

the answer is d

hope this