A cylindrical vase has a diameter of 6 inches. At the bottom of the vase, there are 8 marbles, each of diameter 3 inches. The vase is filled with water up to a height of 10 inches. Which of the following could be used to calculate the volume of water in the vase? (6 points) π(10in)2(3in) − 1.5( four over three π(8in)3) π(3in)2(10in) − 1.5( four over three π(8in)3) π(10in)2(3in) − 8( four over three π(1.5in)3) π(3in)2(10in) − 8( four over three π(1.5in)3) I got the answer as the fourth one however im unsure if I am correct.

  π(3 in)²(10 in) -8(4/3)(1.5 in)³

Step-by-step explanation:

The volume of a cylinder with a radius of 3 inches and a height of 10 inches is ...

  V = πr²h = π(3 in)²(10 in)

The volume of 8 spheres with a radius of 1.5 inches is ...

  V = 8(4/3)πr³ = 8(4/3)π(1.5 in)³

The volume occupied by the water is the volume of the cylinder not occupied by the spheres. So, it is ...

  V = π(3 in)²(10 in) -8(4/3)(1.5 in)³ . . . . . . matches the 4th choice

160

step-by-step explanation:

idk

i hope i

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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