What is the vertex of y=-3x^2+6x+15? Help is much appreciated.

(1, 18)

Step-by-step explanation:

Rewrite the equation in vertex form by completing the square for -3x^2 + 6x + 15. This = -3(x - 1)^2 + 18.

Set y equal to the new right side.

y = -3(x - 1)

Use the vertex form, y = a(x - h)^2 + k, to determine the values of a, h, and k.

a = -3

h = 1

k = 18

Vertex = (h, k) / (1, 18)

the balance is found at the link

step-by-step explanation:

9 x 8 divided by (5-3)=36