The diagram shows two shapes A and B. Prove that both of them have equal perimeter.

see explanation

Step-by-step explanation:

Calculate the perimeters by summing the measures of the sides.

Left figure ( starting with base and summing clockwise )

x + 5 + (x - 6) + (y - 5) + 6 + y ( brackets are the measure of the indents )

= x + 5 + x - 6 + y - 5 + 6 + y

= 2x + 2y

Right figure ( starting with base and summing clockwise )

x + 2 + (x - 3) + (y - 2) + 3 + y

= x + 2 + x - 3 + y - 2 + 3 + y

= 2x + 2y

Both figures have perimeters of 2x + 2y cm

1. minimum

2. 6400

3. eight

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geometry: triangles

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call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

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