Can anyone plz help me

vertex (-4,-1)

2nd point ( 0,31)

Step-by-step explanation:

f(x) = 2x^2 + 16x + 31

First find the vertex

The x coordinate of the vertex is -b/2a  where ax^2 +bx +c

-16/ 2(2) = -16/4 = -4

Substitute into the function

f(-4) = 2 ( -4)^2 +16(-4) +31

       = 2 *16-64 + 31

       = 31 -64 +31

       = -1

The vertex is at ( -4,-1)

Another point can be x=0

f(0) = 0+16(0)+31

     = 31

( 0,31)

this may not be at all, but i use the same website you're using for school, and if i'm stuck doing one of these i try to look for it on the section.