Move the center of the circle horizontally to the left and then to the right of the y-axis. How does the equation of the circle change as the center crosses the y-axis?

The equation of a circle centered in the point (a, b) and with a radius R.

(x - a)^2 + (y - b)^2 = R^2

Then, if you move the circle to the left, then you are decreasing the value of b.

Where b = 0 means that the center of the circle lies on the y-axis.

When you move the graph to the right you will be increasing the value of b.

seems like d

step-by-step explanation:

the correct option is 2.

step-by-step explanation:

according to the given information triangle abc is a right angle triangle with right angle at a. segment ab is 5 and segment ac is 7. point d is on segment bc and angles adb and adc are right angles.

it is given that triangles abd, cad, and cba are similar.

two triangles are similar if their corresponding sides are proportional.

in triangle cba, using pythagoras theorem

                      )

triangle abd and cba are similar,

                            (2)

triangle cad and cba are similar,

                      )

using (1), (2) and (3), we get

hence proved.

therefore option 2 is correct.