What is the factorization of 2x^2+28+98

Step 1:

To solve this, we have to add the terms without any variables together.

Step 2:

To factor this, we have to find the multiples of 2x^2 and 126.

Now, we can factor these numbers like this:

When we multiply the numbers, we get 2x^2 + 126, and when we separate 126, we get our original question, so that means our factoring is correct.

(0.2)+(-8)=0.3+-3+0.3m is the equation i guess? ?

step-by-step explanation: