water drips from a faucet at a rate of 41 drops/ minute. Assuming there are 15,000 drops in gallon, how many minutes would it take for the dripping faucet to fill a 1 gallon bucket? Round your answer to the nearest whole number

370 minutes.

Explanation:

You can calculate the time by using the formula of rate:

 rate = amount / time = number of drops / time

From which you clear the time:

time = number of drops / rate

The rate and the number of drops are given: 41 drops / minute and 15,000 drops (since that is the number of drops in 1.00 gallons).

Therefore, time = 15,000 drops / 41 drops / minute = 365.85 minutes

You have to use the correct number of significant figures, which is the least number of significant figures in every factor. 41 has two significant figures, 15,000 also has two significant figures, while 1.00 has three significant figures.

So you must round 365.85 minutes to two significant figures.

That is 370 (365 is round up to 370).

y = - 6

step-by-step explanation:

given the point (- 2, y) lies on the graph then it is a solution of it's equation.

substitute x = - 2 into the equation for value of y

y = 3(- 2) = 3 × - 2 = - 6

the point on the graph is (- 2, 6)

answer: plz put a pic in so i can answer it

step-by-step explanation: