50 POINTS PLEASE HELP will mark brainlest COMPRESSION BY A FACTOR OF 2 photos attached

Point A'(-1,5)     ........ corrected A' instead of A

Point B'(3,-3)

Step-by-step explanation:

The current function has vertex (2,-4), and passes through (6,0).

Using the standard formula

y = a(x-h)^2+k

we have

h = 2, k=-4

parabola passes through (6,0) =>

0 = a(6-2)^2 -4 = 16a -4

a = 1/4

so equation of given curve is

f(x) = (1/4)(x-2)^2-4

If the curve is compressed horizontally by a factor of 2, then the image is

g(x) = (1/4)(2(x-2))^2-4

=(x-2)^2 -4

Given A(-4,5), B(4,-3)

f(-4) = 5  

f(4) = -4

With a compression factor of 2, coordinates of y do not change.

for point A'

5 = (x-2)^2 -4

5 = (x-2)^2 -4

(x-2)^2 = 9

(x-2) = +/- 3

x-2 = -3, x = -1  (to the left of vertex, ok)

x-2 = +3, x = 5 (to the right of vertex, alternate point x)

Point A'(-1,5)     ........ corrected A' instead of A

For point B'

y = -3

-3 = (x-2)^2-4

(x-2)^2 =1

x-2 = +/- 1

x-2 = +1, x=3 (to the right of vertex, point required)

x-2 = -1, x= 1 (to the left of vertex, alternate point Y)

Point B'(3,-3)

answer: i think the answer is etheir c or d but i don't know which one but have a good day!

step-by-step explanation:

the answer is 62