The snowfall from this snowstorm above covered most of IA, northern IL, northern IN, and southern MI. While some locations in that swath saw over a foot of snow, let’s assume the average depth of the snow over this area was 8 inches. If the total area covered by the 8 inch average depth was 72,150 square miles, what percentage of the volume of the Grand Canyon would this amount of snow fill?

Percentage volume of the Grand Canyon filled by the snow = 0.911 %

Step-by-step explanation:

This question is incomplete; please find the complete question in the attachment.

Given :

Area of the snow cover = 72150 square miles

Depth of the snow = 8 inches

Volume of the Grand Canyon = 4.166 × 101² m³

Solution:

Area of the snow cover = 72150 square miles

≈ 72150 × 2589988 square meter

≈ 1.868 × 10¹¹ square meter

Depth of the snow = 8 inches ≈ 0.2032 m

Volume of the snow on this area = Area × depth of the snow

                                                       = 1.868 × 10¹¹ × 0.2032

                                                       = 3.796 × 10¹⁰ m³

Volume of the Grand Canyon = 4.166 × 10¹² m³

Percentage volume of the Grand Canyon filled by the snow

=

=

= 0.911%

answer is 144

step-by-step explanation:

b. would be the answer : )

step-by-step explanation:

step 1: add -16x to both sides.

16x−4y+−16x=64+−16x  

−4y=−16x+64

step 2: divide both sides by -4.

−4y /-4 = -16x + 64/-4

answer:   y=4x−16

hope i'm right