The ten's digit in a two-digit number is 1 greater than the one's digit. If we interchange the digits in the number, we obtain a new number that, when added to the original number, results in the sum 187. Find this number.

98

Step-by-step explanation:

Let's say the tens place is x and the ones place is y.

The tens place is one more than the one's place:

x = y + 1

Reversing the digits, plus the original number, is 187:

(10x + y) + (10y + x) = 187

11x + 11y = 187

x + y = 17

Substituting:

y + 1 + y = 17

2y = 16

y = 8

x = 9

The number is 98.

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step-by-step explanation:

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