For the piecewise function, find the values g(-2), g(3), and g(4). X +5, for x<3
g(x)=
6- X, for x>3
9(-2)=
g(3)=
9(4)=

g(-2)= -2 + 5 =3  ( here we chose the function g(x)= x+5 as x< 3)

Step-by-step explanation:

g(3)= is not defined ( function is defined for x<3 and x>3 but not x=3)

g(4) = 6-4=2 ( here we chose the function g(x)= 6-x as x> 3)

guess at question:

a vertical line intersects the graph of g(x,y) = 0 at two points. what conclusion follows about the function f(x) implicitly defined by g(x,f(x)) = 0?

the domain of f(x) cannot include the x coordinate of any such vertical line.

informally, f(x) is not a function, and

g(x,y)=0 cannot be solved for y uniquely.

the relation r = {(x,y) such that g(x,y) = 0} is a function if

for all (a,b) ∊ r and (c,d) ∊ r, a=c implies b=d.

step-by-step explanation: