This is a cross-sectional view of candy bar ABC. A candy company wants to create a cylindrical container for candy bar ABC so that it is circumscribed about the candy bar. If = 4 cm, what is the smallest diameter of wrapper that will fit the candy bar?

Step-by-step explanation:

No figure supplied, so lots of assumptions needed.

Assume side length of triangle is 4 cm.  

( If = 4 cm  means ??)

Assume ABC is equiangular, all three angles are 60 degrees.

(This is a cross-sectional view, but don't see any)

Side length = 4

altitude of triangle = 4 sin(60) = 2sqrt(3)

radius of circumscribed circle of equilateral triangle

R = (2/3) altitude

= (2/3)*2sqrt(3)

= (4/3)sqrt(3)

Diameter

D = 2R

= (8/3) sqrt(3)

5x + 3y = - 4

step-by-step explanation:

the equation of a line in standard form is

ax + by = c ( a is a positive integer and b, c are integers )

express the line first of all in slope- intercept form

y = mx + c ( m is the slope and c the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (7, - 3) and (x₂, y₂ ) = (4, - 8)

m = = -

y = - x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (4, - 8 ), then

- 8 = - + c ⇒ c = -

y = - x - ← in slope-intercept form

multiply all terms by 3 to eliminate the fractions

3y = - 5x - 4 ( add 5x to both sides )

5x + 3y = - 4 ← in standard form