How to do this question plz

148 cm ^2

Step-by-step explanation:

Hey there!

Well is the area of the base is 30 then we can conclude that the side lengths are 5 and 6.

Then if the volume is 120 we can do,

120 ÷ 30 = 4

So the height is 4 cm.

Now we already have the area of the base we just need to find the area of the rest of the rectangles.

If the bottom base is 30 then the top base is also 30.

30 + 30 = 60cm^2

Now we can do the two rectangles on the side that have side lengths of 5 and 4.

5*4 = 20

20+20 = 40 cm^2

Now we can do the two final rectangles that have side lengths of 6 and 4.

6*4=24

24 + 24 = 48 cm^2

Now we can add all the areas up,

48 + 40 + 60

= 148 cm^2

Hope this helps :)

geometry: triangles

solvers

lessons

answers archive

call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

25.45584

proofs involving isosceles triangles often require special consideration because an isosceles triangle has several distinct properties that do not apply to normal triangles.(more about triangle types) therefore, when you are trying to prove that two triangles are congruent, and one or both triangles, are isosceles you have a few theorems that you can use to make your life easier.

step-by-step explanation:

an isosceles triangle has two congruent sides and two congruent angles. the congruent angles are called the base angles and the other angle is known as the vertex angle. ∠bac and ∠bca are the base angles of the triangle picture on the left. the vertex angle is ∠abc