The circle below is centered at the point (-3,4) and had a radius of 3. What is it equation? ( top answers gets )

( x+3) ^2 + ( y-4) ^2 = 9

Step-by-step explanation:

The equation of a circle can be written as

( x-h) ^2 + ( y-k) ^2 = r^2

Where ( h,k) is the center and r is the radius

( x--3) ^2 + ( y-4) ^2 = 3^2

( x+3) ^2 + ( y-4) ^2 = 9

x= -3 and

step-by-step explanation:

to find the roots of a cubic, use division or factoring to find the factors then set equal to 0. as this is a difference of cubes, it factors into

where a is the cube root of .

here   this is 27 and the cube root of 27 is 3. so we write using the form:

.

set each factor to 0 and solve for x.

x-3=0

x=3

the quadratic expression does not factor and must be solved using the quadratic formula.

where a = 1, b=3, and c=9

this cubic has two complex roots.

so then what are you asking?

step-by-step explanation: