A sample of 13 small bags of the same brand of candies was selected. Assume that the population distribution of bag weights is normal. The weight of each bag was then recorded. The mean weight was 3 ounces with a standard deviation of 0.15 ounces. The population standard deviation is known to be 0.1 ounce. Required:a. Construct a 98% confidence interval for the population mean weight of the candies. b. State the confidence interval. (Round your answers to three decimal places.)c. Draw the Graph

The answer is below

Step-by-step explanation:

Given that:

Mean (μ) = 3 ounces. standard deviation (σ) = 0.15, sample size (n) = 13 and confidence (C) = 98%

α = 1 - C = 1 - 0.98 = 0.02

α/2 = 0.02/2 = 0.01.

The z score of 0.01 (α/2) corresponds to the z score of 0.49 (0.5 - 0.01) which from the normal distribution table is 2.33.

The margin of error (E) is:

The confidence interval = μ ± E = 3 ± 0.1 = (2.9, 3.1)

The confidence interval is between 2.9 ounce and 3.1 ounce

hit or miss i guess they never miss huh

step-by-step explanation:

you got a boyfriend i bet he doesnt kiss ya

6 adults and 9 children went.

a + c = 15

12a + 9c = 153

12(6) + 9(9) = 153

72 + 81 = 153