Which of the following explains how ΔAEB could be proven similar to ΔDEC using the AA similarity postulate? A) ∠AEB ≅ ∠CED because vertical angles are congruent; reflect ΔCED across segment FG, then translate point D to point A to confirm ∠EAB ≅ ∠EDC. B)∠AEB ≅ ∠CED because vertical angles are congruent; rotate ΔCED 180° around point E, then dilate ΔCED to confirm segment EB ≅ segment EC. C) ∠AEB ≅ ∠DEC because vertical angles are congruent; rotate ΔCED 180° around point E, then translate point D to point A to confirm ∠EAB ≅ ∠EDC. D) ∠AEB ≅ ∠DEC because vertical angles are congruent; reflect ΔCED across segment FG, then dilate ΔCED to confirm segment EB ≅ segment ED

C

Step-by-step explanation:

We can eliminate B and D because the AA postulate includes 2 corresponding congruent pairs of angles, not sides. A does not make sense because you can't reflect ΔCED across FG and then translate point D to A, you need to rotate it 180°. Therefore, the answer is C.

question 1 is 8, question 2 is 9, question 3 is 24

step-by-step explanation:

now, the numbers they give you at the top are the key. from there, you just have to plug and chug! let's try 1, 2, and 3!

key: a=3, b=5, c=6

1. a+5

remember, a=3, so we plug that in to get 3+5=8

2. 15-c

c=6, so we plug that in to get 15-6=9

3. 4b

b=6, so we plug it in to get 4*6=24

time to try the rest on your own! if you put the answers below in a comment, i'll check them for you!