A professor graded the final exams and found that the mean score was 70 points. Which of the following can you conclude? A- All of the above.

B- The median score was 70 points.

C- 50% of the students scored below 70 points.

D- This would be a normal distribution.

 C) 50% of the students scored below 70%

Step-by-step explanation:

Mean is the average.  To find the mean (aka average) you add up all of the scores and divide by the number of tests.  

B) The mean can be 70 without any test scoring 70% so B is not true.

A) Since B is not true, then A is not a valid option.

D) We don't know any of the other data so don't know if it is skewed left, skewed right, or normal.  Therefore, option D is not true.

C) If the average is 70%, then half received grades above that score and half received grades below that score.  So, option C is TRUE!

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."

stop cheating

step-by-step explanation: