Find the equation of a circle with PQ as diameter, where P(2,-6) and Q(-6,-4)

y=-¼x+⁴⁴/8

Step-by-step explanation:

p(2,-6). Q(-6-4)

p (x¹,y¹). Q(x²,y²)

1) find the gradient(slope)

gradient=y²-y¹

x²-x¹

gradient = -4-(-6)

-6-2

gradient= -4+6

-6-2

gradient=²/-8

2)equation is supposed to be in the form of y=mx+c

where m is the gradient

thus.

gradient=y²-y¹

x²-x¹

when finding the equation we only use one of the values of the coordinates leaving the other as an unknown value.

2 = y-(-4)

-8 x-(-6)

2 =y+4

-8. x+6

remove the denominators by cross multiplying that is:

2(x+6)= -8(y+4)

2x+12= -8y-32

express in the format y=mx+c

2x+12+32=-8y

2x+44=-8y.

divide all sides by -8 to remain with y

²/-8x+⁴⁴/-8=y

-¼x+ -⁴⁴/8=y

y=-¼x-⁴⁴/8

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

eventually after a few more steps, your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x