Tre and Hector want to calculate the maximum possible throw at this field. They calculate that the farthest point on the field would be the center fielder standing back at the dead center wall at point (322, 322). Suppose the center fielder threw the ball from here to home base.

How far is the throw?

answer:

c. the third graph

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116

i believe that the slope of the line is -5

step-by-step explanation: