To evaluate the integral 0 (t1/3 − t2/3) dt −1 , first use the property of definite integrals, that is, b (f(x) + g(x)) dx a = b f(x) dx a + b g(x) dx. a Therefore, 0 (t1/3 − t2/3) dt −1 = 0 t1/ dt −1 ---Select--- 0 t /3 dt. −1

a) 0.25x times 3. (could be wrong on equation.)

b) 2.25 pound of dark chocolate. (can i eat all the chocolate? plz? anyway, again, could be wrong, but i hope im right. all the chocolate together should be 5.25 pounds)

have a good day!

answer: what is the question you're trying to ask?

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