Arrange the functions for which the result is a non-infinite value and the limit exists in ascending order of their limit values as x tends to infinity.

The arrangement of the functions for which the result is a non-infinite value and the limit exists in ascending order of their limit values as x tends to infinity is given below;

m(x), k(x), i(x), g(x), l(x)

Step-by-step explanation:

Since the limit of all the function as x tends to infinity is a non-infinite value, the limit converges.

We must understand that lim of a/x as x tends to infinity is equivalent to zero where a is any constant.

Let's take the function one after the other.

For l(x) = 5x²-4/x²+1

Dividing through by highest power of x i.e x²

lim x-> \infty 5x²-4/x²+1

lim x-> \infty 5x²/x²-4/x²/x²/x²+1/x²

lim x->∞ 5-4/x²/1+1/x²

=5-4/∞/{1+1/∞²}

= 5-0/1+0

= 5/1

= 5

Hence lim x-> \infty 5x²-4/x²+1 = 5

Find the remaining solution in the attachment below.

sorry, can't i suggest going to algebra.com

step-by-step explanation: