A small plane flies 760,320 yards in 2 hours. Use the formula d = rt, where d represents distance, r represents rate, and t represents time, to answer the following questions. Show your work. Part A: Rearrange the distance formula, d = rt, to solve for rate. (2 points)

Part B: Find the plane's rate in yards per hour. (3 points)

Part C: Find the plane's rate in miles per hour. (3 points)

Part D: Which unit, yards, or miles, makes more sense to use in this scenario, and why? (2 points)

Step-by-step explanation:

A) d = rt

  r = d/t . . . . . divide by the coefficient of r

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B) For the given numbers, the rate is ...

  760,320 yd/(2 h) = 380,160 yd/h

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C) There are 1760 yards in a mile, so we can convert units this way:

  (380,160 yd/h)·(1 mi)/(1760 yd) = 216 mi/h

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D) For many everyday measurements, we like to have the numbers be in the range of 1 to 1000. We often choose units to make the numbers come out that way. Here, unit of 'miles per hour' give a numerical value in that range, so are suitable units for the speed.

(Another suitable unit might be 'yards per second', for which the numerical value would be 105.6. Most of us don't have experience with speeds expressed in yards per second, so would not find those units 'intuitive.')

7 ft 6 in means 7 1/2, because 6 in is 1/2 of a foot. 7 ft 8 in means 7 2/3 because 8 in is 2/3 of a foot. 23/3 = 7 2/3. 15/2 = 7 1/2.

23/3   *   15/2   = 57 1/2

step-by-step explanation: