In 5 hours a small plane can travel downwind for 4000 kilometers or upward 3000 kilometers. Find the speed of this plane with no wind and the speed of the wind current.

write as an equation

the speed of the plane with no wind is 700 km/h and the speed of the wind is 100 km/h

Step-by-step explanation:

Let V be the speed of the plane and v the speed of the wind. Down current, they are in opposite directions, and the plane travels a a distance of 4000 km in 5 hours,so

5(V - v) = 4000

V - v = 800    (1)

For upwind movement, since the plane travels 3000 km in 5 hours, so

5(V + v) = 3000

V + v = 600 (2)

adding equations (1) and (2), we have

V - v = 800

+

V + v = 600

2V = 1400

V = 1400/2 = 700 km/h

subtracting equations (2) from (1), we have

V - v = 800

-

V + v = 600

-2v = 200

v = -200/2 = -100 km/h

So, the speed of the plane with no wind is 700 km/h and the speed of the wind is 100 km/h

i use my brain for prombles like this maybe you could try it

step-by-step explanation:

p ÷ r = tan(x)

step-by-step explanation:

given that there is a figure below shows a right triangle: a right triangle is shown with hypotenuse equal to q units and the length of the legs equal to p units and r units.

graph is missing so i will create the graph as per given information.

the angle between the legs having lengths p units and q units is y degrees. the angle between the legs having lengths r units and q units is x degrees.

now we need to find about what is p ÷ r equal to.

so we can use trigonometric ratio tan(x)=[altitude]/[base] to find the value of p ÷ r, because p is the altitude and r is the base.

p ÷ r=tan(x)

hence final answer is p ÷ r=tan(x).