You are making a scaledrawing of a room using a scale of1 inch : 4 feet. a. The room is 14 feet by 18 feet. Find itsdimensions in the drawing. b. A sofa in the room has a length of 6 feet. Find the length of the sofa in thedrawing. c. You want to enlarge the scale drawing. How would you change the scale todouble the dimensions of the drawing?Explain.

a. 3.5 inches by 4.5 inches

b. 1.5 inches

c. Divide 48 inches by 2 and multiply 1 inch by 12 to get a scale of 1 : 2

Step-by-step explanation:

A scale is a representative fraction showing the relationship between length on a drawing and actual length.

i.e scale =

 scale = 1 inch : 4 feet

a. The dimensions in the drawing can be determined as;

1 inch : 4 feet implies an inch on the drawing equates 4 feet on actual length.

= 3.5 inches

= 4.5 inches

Dimensions on drawing is 3.5 inches by 4.5 inches.

b. The length of the sofa is 6 feet, its length on the drawing is;

= 1.5 inches

c. To enlarge the scale so as to double the dimensions of the drawing, we have;

12 inches = 1 feet

4 feet = 4 × 12 = 48 inches

given scale = 1 inch : 48 inches

Thus, divide 48 inches by 2 and multiply 1 inch by 12.

scale = 12 inch : 24 inch

scale = 1 : 2

To double the dimensions of the drawing, the scale required is 1 : 2. This implies that a unit measure on the drawing is synonymous to 2 measures on the actual reading.

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.