Find the critical numbers of the function. (Enter your answers as a comma-separated list. If an answer does not exist, enter DNE.) f(x) = 8x3 − 12x2 − 48x

Step-by-step explanation:

Given the function f(x) = 8x³ − 12x² − 48x, the critical point of the function occurs at its turning point i,e at f'(x) = 0

First we have to differentiate the function as shown;

Hence the critical numbers of the function are (2, -1)

-22

times both sides by 2, times () by 8, add alile terms, move terms, add alike and caculate divide both sides by 3