Suppose that a box contains 6 cameras and that 3 of them are defective. A sample of 2 cameras is selected at random. Define the random variable X as the number of defective cameras in the sample. Write the binomial probability distribution for X . Round to two decimal places.

X ~ Binom (n = 6, p = 0.50)

Step-by-step explanation:

We are given that a box contains 6 cameras and that 3 of them are defective.

A sample of 2 cameras is selected at random.

Let X = Number of defective cameras in the sample.

The above situation can be represented through binomial distribution;

where, n = number of trials (samples) taken = 2 cameras

             x = number of success

            p = probabilitiy of success which in our question is probability that  

                  cameras are defective, i.e. p = = 0.50

So, X ~ Binom (n = 2, p = 0.50)

Now, the binomial probability distribution for X is given by;

Here, the number of success can be 0, 1, or 2 defective cameras.

sin3a=12/15

step-by-step explanation:

since one side was multiplied by 3 the other side must also be multiplied by 3.

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step-by-step explanation: