Find two positive numbers satisfying the given requirements. The sum of the first and twice the second is 400 and the product is a maximum.

Step-by-step explanation:

Let the first number be 'a' and the second number be 'b'. If the sum of the first and twice the second is 400 then;

a+2b = 400

From the equation above, a = 400 - 2b ... 2

If the product of the numbers is a maximum then;

ab = (400-2b)b

let f(b) be the product of the function.

f(b) = (400-2b)b

f(b) = 400b-2b²

For the product to be at the maximum then f'(b) must be equal to zero i.e f'(b) = 0

f'(b)= 400-4b = 0

400-4b = 0

400 = 4b

b = 400/4

b = 100

Substituting b= 100 into the equation a = 400 - 2b to get a;

a = 400 - 2(100)

a = 400 - 200

a = 200

The two positive integers are 100 and 200.

a.   since the profit made in 2012 is equal to the profit made in 2014, the profit is symmetric about the line y = 120,000.

step-by-step explanation:

you need to show the graph

step-by-step explanation: