Point R divides PG in the ratio 1:3. If the x-coordinate of R is -1 and the x-coordinate of P is -3, what is the x-coordinate of Q

option C . 5

Step-by-step explanation:

For two points (x1,y1) and (x2,y2) divided by a point p in ratio m:n then coordinates of that point is given by

p    :  (nx1+mx2)/(m+n),  (ny1+my2)/(m+n),  

Given

x coordinate of P (-3)

x  coordinate of Q (a) since we have to find it , let it be a

x coordinate of R(-1)\

ratio = 1:3

Using the above formula to find the point of division

we can get value of x coordinate for point Q

x  coordinate of R = 3*-3 + 1*a/(1+3)

-1 = (-9 + a)/4

=> -4 = -9 +a

=>a = -4+9 = 5

Thus, x  coordinate of Q is 5

answer: 370

step-by-step explanation:

remember use pemdas! there are no parentheses or exponents so lets move onto the first part of the equation: multiplication and division. first, lets break the first part of the equation up into something easier using the distributive property. 28 * 12= (20 *12) + (8*12) you know that 20*12 is 240 and 8*12 is 96. add them and you get 336. then, lets solve the last part of the equation (the last part of pemdas is addition and subtraction). 336 plus 34 is 370. hope this !

answer: translate the circles so they share a common center point and dilate circle y by a scale factor of 3.