Consider the function f(x) = x2. Which of the following functions shifts f(x) downward 5 units and to the right 3 units?
A)f(x) = (x + 3)2 - 5
B) f(x) = (x - 3)2 - 5
C) f(x) = (x - 5)2 - 3
D) f(x) = (x - 5)2 + 3

f(x) = (x - 3)² - 5

Step-by-step explanation:

equate equation to 0

(x - 3)² = 0

take the square root on both sides

x - 3 = 0

add 3

x = 3

If x = 3 then you are moving to 3 units to the right.

- 5 means you are going downward 5 units.

option (a)

step-by-step explanation:

step 1:   take 2 number whose product equal to 25..

and sum of those two number are -10

step: 2 for example here if we take 5,5 are the number,,

5*5=25

and

5+5=10

but we need -10

so if we take   -5,-5

so -5*-5=25

and -5+(-5)=-10

s0

come the equation

replace -10x by these number

like -5x -5x+25

take common

x(x-5)-5(x-5)=0

(x-5)(x-5)=0