What is the diameter of the base of the cone below, to the nearest foot, if the volume is 314 cubic feet? Use π = 3.14.

This question is incomplete because it lacks the required diagram. Please find attached the diagram required to answer the question.

14 feet

Step-by-step explanation:

The volume of a cone = 1/3 πr²h

In the above question, we are given the volume = 314 cubic feet

the height is given in the attached diagram = 6ft

Step 1

We find the radius.

From the formula for the volume of a cone, we can derive the formula for radius of the cone.

Radius of the cone = √(3 × V/π × h

π = 3.14

Radius of the cone = √( 3 × 314 /3.14 × 6

Radius of the cone = √942/3.14× 6

Radius = √50

= 7.0710678119feet

Step 2

Diameter of the cone = Radius of the cone × 2

= 7.0710678119 × 2

= 14.142135624 feet

Approximately to the nearest foot = 14 feet

Therefore, the diameter of the cone to the nearest foot = 14 feet.

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)

c

step-by-step explanation: