The baseball team has a double-header on Saturday. The probability that they will win both games is 42%. The probability that they will win the first game is 60%, What is the probability that the team will win the second game given that they have already won the first game?

24 units

step-by-step explanation:

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116

14.29%

step-by-step explanation:

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