Given: ΔABC, AC = BC, AB = 3 CD⊥ AB, CD = 3 Find: AC

3.35 (3 sig.fig)

Triangle ABC

AC = BC, AB = 3, CD perpendicular to AB, CD =3

AC (Hypotenuse)

AC = BC shows that Triangle ABC is an isosceles triangle.

As CD is perpendicular to AB, and, both sides

(AC & BC) have equal angles and length, making the line CD cut right across the triangle.

(Point D is in the middle of Line AB)

Resulting in 2 EQUAL triangles in Triangle ABC.

To find one of the 2 triangles:

1. Take Line AB and divide it in half as both sides are equal.

Line AD = 3 / 2

= 1.5

2. Use the Pythagoras Theorem to find Line AC (Hypotenuse). [c^2 = a^2 + b^2]

a : Line AD = 1.5

b : Line CD = 3

c^2 = 1.5^2 + 3^2

c^2 = 2.25 + 9

c^2 = 11.25

c= (Square Root) 11.25

c= 3.35 (3 significant figure)

Therefore, the answer is:

3.35

answer:

a=9

step-by-step explanation: lmk if you need a explanation