Missing Portion on Spinner: So theres a circle,

2/3 is covered,

1/6 is covered,

and 1/9 is covered

what fraction is the portion that isn't covered

Explanation:

The fractions 2/3, 1/6 and 1/9 have the denominators 3, 6 and 9. The LCM is 18, so the LCD of the fractions is 18.

2/3 = 12/18 after multiplying top and bottom by 6

1/6 = 3/18 after multiplying top and bottom by 3

1/9 = 2/18 after multiplying top and bottom by 2

The three original fractions 2/3, 1/6, and 1/9 are equivalent to 12/18, 3/18, and 2/18 in that exact order.

With the fractions all having the same denominator, we can add the numerators to place over the common denominator

12/18 + 3/18 + 2/18 = (12+3+2)/18 = 17/18

After combining all of the shaded areas, we have 17/18 of the circle shaded in with 1/18 of the circle not shaded in.

You subtract 17/18 from 1 to get 1/18

1 - (17/18) = 18/18 - 17/18 = (18-17)/18 = 1/18

You could think of it like having 18 slices of cake total, and 17 are eaten by guests, so 18-17 = 1 is left over out of the 18 overall. So 1/18 of the cake hasn't been eaten.

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v