Vince went on a 333 day hiking trip. Each day, he walked 3\4 the distance that he walked the day before. He walked 83.2583, point, 25 kilometers total in the trip.

x= 36 km

Step-by-step explanation:

Vince went on a 3 day hiking trip. Each day, he walked 3/4 the distance that he walked the day before. He walked 83.25 kilometers total in the trip. How far did Vince walk on the 1st day of the trip?

Assume vince walked x km on the first day .

The following equation can be formed

x + 3/4 x + (3/4)^2 x = 83.25

x + 0.75x + 0.5625x = 83.25

Add the like terms

2.3125x = 83.25

Divide both sides by 2.3125

x = 36 km.

7.9m and 4.3°

step-by-step explanation:

let east be +x and north be +y, x = distance * cos θ, y = distance * sin θ  

for 3.5 south, y = -3.5  

for 8.2, x = 8.2 * cos 30 and y = 8.2 * sin 30  

for 15 west, x = -15  

total x = 8.2 * cos 30 – 15 ≈ -7.9  

total y = -3.5 + 8.2 * sin 30 = 0.6  

magnitude = [(8.2 * cos 30 – 15)^2 + 0.6^2)]^0.5  

the magnitude is approximately 7.9 m  

tan θ = y/x = 0.6/-7.9  

the angle is approximately 4.3˚ north of west