Using Normal Distribution, what is the area to the right of 0.72 under the standard normal curve?

0.2358

Step-by-step explanation:

Using Normal Distribution, under the  standard normal curve

The area to the right of z is given by P(Z>z)=1-P(Z<z)

So, the area to the right of z= 0.72 under the  standard normal curve would be:

P(Z>0.72)=1-P(z<0.72)

=1-0.7642   [By using p-value table]

= 0.2358

Hence, the area to the right of z= 0.72 under the  standard normal curve is 0.2358 .

a - base

b - exponent

so,