Convert -1.2i - 1.6j to polar cordinates

Step-by-step explanation:

z=xi+yj

x=-1.2=r cosθ (say)

y=-1.6=r sinθ(say)

square and add

r²cos²θ+r² sin ² θ=(-1.2)²+(-1.6)²=1.44+2.56=4

r²=4

r=2

divide

tanθ=y/x=-1.6/(-1.2)=16/12=4/3

θ=tan ^{-1}(4/3)≈53.13°

so polar coordinates are (2,53.13°)

you can't solve x because it is 2 linear equation and you only have one equation