A particle is moving along a coordinate axis such that its position is defined as s(t) = 4t3 − 2t2 − 14, where t ≥ 0. Find the rate at which the particle's position is changing at t = 3. 96
76
48
30

∠acb = 8°

step-by-step explanation:

∠xba lies on the circle and is half the measure of the intercepted arc ax

hence

measure of arc ax = 2 × 42° = 84°

∠acb is outside the circle and is

∠acb = (arcab - arcax ), hence

∠acb = 0.5 (100 - 84) = 0.5 × 16° = 8°