Use suitable identities to find the product of 1) (x-4) (x+10) 2) (3x+4) (3x +5) 3) (-3a +5b +4c)^2

Step-by-step explanation:

(x-4) (x+10)  ⇒ (x+a)(x+b)=x²+(a+b)x+ab

a=-4 , b=10

x²+(-4+10)x+-4(10)

x²+6x-40

(3x+4) (3x +5)

3(x+4/3) *3(x+5/3)  ⇒ identity : (x+a)(x+b)=x²+(a+b)x+ab  

a=4/3    b=5/3

3*3=9

9[x²+(4/3 +5/3)x+4/3(5/3)]

9[x²+9/3 x+20/9]

9x²+27x+20

(-3a +5b +4c)^2  ⇒  

suitable identity is (a+b+c)²= a² + b² + c² + 2ab + 2bc + 2ca

a=-3a , b=5b , c=4c

9a²+25b²+16c²- 30ab +40bc - 24ca

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!