The tens digit is 2 less than the units digit. If the digits are reversed, the sum of the reversed number and the original number is 154. Find the original number.

68

Step-by-step explanation:

Hello, the number is 'ab' meaning that we can write it as 10a +b

For instance 42 = 10*4 + 2

So, a = b - 2

and 10a + b + 10b + a = 154

11(a+b)=154

a+b = 154/11 = 14

We replace a by b - 2

b+b-2 = 14

2b = 14 + 2 = 16

b = 8 and then a = 6

the original number is 68.

Thanks

idn

step-by-step explanation: