Dy
If x= 15t2 and y= 10t2, find
dx

x' = 30t

              y' = 20t

Step-by-step explanation:

To find the derivative, multiply the exponent to the leading coefficient and decrease the exponent by 1.

x = 15t²

x' = 2 · 15t²⁻¹

  = 30t¹

  = 30t

y = 10t²

y' = 2 · 10t²⁻¹

   = 20t¹

   = 20t

the answer on e2020 is

10

4/5

3/5

4/3

step-by-step explanation:

x = central angle apc = measure of minor arc ac

the two angles x and 30 add to 180, so x+30 = 180 and x = 180-30 = 150. the measure of minor arc ac is 150 degrees.

what we need to do from here is find the circumference and then multiply it by x/360 since there are 360 degrees in a circle. in this case, x = 150, so x/360 = 150/360 = 15/36 = 5/12. the shortest distance along the curve from a to c is 5/12 of the distance around the entire circle (aka circumference)

c = circumference

c = pi*d

c = pi*24

c = 24pi

now multiply this by 5/12 to get

distance along minor arc ac = (5/12)*(circumference)

distance along minor arc ac = (5/12)*(24pi)

distance along minor arc ac = 10pi

the formula you can use is

l = (x/360)*pi*d

with

l = length of minor arc

x = central angle

d = diameter

which essentially is the steps we took though a bit differently.